The equation of chord of the circle x2+y2=8 x bisected at the point (4,3) is

Question

The equation of chord of the circle x2+y2=8 x bisected at the point (4,3) is (A) x=3 (B) y=3 (C) x=-3 (D) y=-3

Tardigrade Admin · Accepted Answer

T = S 1 ⇒ x(4)+y(3)-4(x+4)=16+9-32 ⇒ 3 y-9=0 ⇒ y=3

Q. The equation of chord of the circle $x^{2} + y^{2} = 8 x$ bisected at the point $(4, 3)$ is