Question

The equation of auxilary circle of hyperbola $\frac{x^2}{9}-\frac{y^2}{16}=1$

• A. $x^2+y^2=9$
• B. $x^2+y^2=16$
• C. $x^2+y^2=41$
• D. $x^2+y^2=7$

Answer 1

Answer: (A)

Equation of auxilary circle
$\Rightarrow x^2+y^2=9$