The equation of a wave is given by y= A sin ω((x/v)=k), where ω is angular velocity, v be linear velocity. Then dimension off c is

Question

The equation of a wave is given by y= A sin ω((x/v)=k), where ω is angular velocity, v be linear velocity. Then dimension off c is (A)  [ LT ]  (B)  [ T ]  (C)  [T1 ] (D)  [T2 ]

Tardigrade Admin · Accepted Answer

y= sin ω((x/v)-k) Comparing this equation with y=A sin ω((x/v)-t) Dimension of k = dimension of t =[T]

Q. The equation of a wave is given by $y = A sin ω (\frac{x}{v} = k)$ , where $ω$ is angular velocity, $v$ be linear velocity. Then dimension off $c$ is

$[L T]$

$[T]$

$[T^{1}]$

$[T^{2}]$

$y = sin ω (\frac{x}{v} - k)$ Comparing this equation with $y = A sin ω (\frac{x}{v} - t)$ Dimension of
$k =$ dimension of $t$
$= [T]$

Q. The equation of a wave is given by y=Asinω(vx​=k), where ω is angular velocity, v be linear velocity. Then dimension off c is

[LT]

[T]

[T1]

[T2]