The equation of a line is 6x-2=3y-1=2z-2. The direction ratios of the line are

Question

The equation of a line is 6x-2=3y-1=2z-2. The direction ratios of the line are (A) 1, 2, 3 (B) 1, 1, 1 (C)  (1/3),(1/3),(1/3)  (D)  (1/3),(-1/3),(1/3)

Tardigrade Admin · Accepted Answer

The given equation is 6 x-2=3 y-1=2 z-2 ⇒ (x-(1/3)/1)=(y-(1/3)/2)=(z-1/3) This shows that DR's of given equation are (1,2,3).

Q. The equation of a line is $6 x - 2 = 3 y - 1 = 2 z - 2.$ The direction ratios of the line are

$1, 2, 3$

$1, 1, 1$

$\frac{1}{3}, \frac{1}{3}, \frac{1}{3}$

$\frac{1}{3}, \frac{- 1}{3}, \frac{1}{3}$

The given equation is
$6 x - 2 = 3 y - 1 = 2 z - 2$
$\Rightarrow \frac{x - \frac{1}{3}}{1} = \frac{y - \frac{1}{3}}{2} = \frac{z - 1}{3}$
This shows that DR's of given equation are $(1, 2, 3)$ .

Q. The equation of a line is 6x−2=3y−1=2z−2. The direction ratios of the line are

1,2,3

1,1,1

31​,31​,31​

31​,3−1​,31​