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Tardigrade
Question
Mathematics
The equation 2 cos θ - 3 sin θ - A = 0 has real solution in θ, then
Q. The equation 2 cos
θ
−
3
s
in
θ
−
A
=
0
has real solution in
θ
, then
1586
204
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A
A = -4
B
∣
A
∣
≤
13
C
| A | < 5
D
| A | = 5.
Solution:
Correct answer is (b)
∣
A
∣
≤
13