The entropy change (in cal K -1 m o l -1 ) when one mole of an ideal gas at 27° C is expanded reversibly from one litre to 10 litre is

Question

The entropy change (in cal K -1 m o l -1 ) when one mole of an ideal gas at 27° C is expanded reversibly from one litre to 10 litre is (A) zero (B) 2.6 (C) 4.6 (D) 5.4

Tardigrade Admin · Accepted Answer

Δ S=2.303 n R log ((V2/V1)) =2.303 × 1 × 2 × log (10) =4.606 cal K -1 mol -1

Q. The entropy change (in cal $K^{- 1} m o l^{- 1}$ ) when one mole of an ideal gas at $2 7^{\circ} C$ is expanded reversibly from one litre to $10$ litre is

zero

2.6

4.6

5.4

$Δ S = 2.303 n R lo g (\frac{V _{2}}{V _{1}})$
$= 2.303 \times 1 \times 2 \times lo g (10)$
$= 4.606 c a l K^{- 1} m o l^{- 1}$

Q. The entropy change (in cal K−1mol−1 ) when one mole of an ideal gas at 27∘C is expanded reversibly from one litre to 10 litre is

zero

2.6

4.6

5.4

ΔS=2.303nRlog(V1​V2​​) =2.303×1×2×log(10) =4.606calK−1mol−1

Q. The entropy change (in cal $K^{- 1} m o l^{- 1}$ ) when one mole of an ideal gas at $2 7^{\circ} C$ is expanded reversibly from one litre to $10$ litre is

$Δ S = 2.303 n R lo g (\frac{V _{2}}{V _{1}})$
$= 2.303 \times 1 \times 2 \times lo g (10)$
$= 4.606 c a l K^{- 1} m o l^{- 1}$