The enthalpy of vaporization of liquid is 30 kJ mol- 1 and entropy of vapourisation is 75 J mol- 1K- 1 . The boiling point of the liquid at 1 atm is

Question

The enthalpy of vaporization of liquid is 30 kJ mol- 1 and entropy of vapourisation is 75 J mol- 1K- 1 . The boiling point of the liquid at 1 atm is (A) 250 K (B) 400 K (C) 450 K (D) 600 K

Tardigrade Admin · Accepted Answer

ds=(d qr e v/T)⇒ 75=(30 × 103/T)⇒ T=400 K Hence (B) is correct option.

Q. The enthalpy of vaporization of liquid is $30 k J m o l^{- 1}$ and entropy of vapourisation is $75 J m o l^{- 1} K^{- 1}$ . The boiling point of the liquid at 1 atm is

250 K

400 K

450 K

600 K

$d s = \frac{d q _{re v}}{T} \Rightarrow 75 = \frac{30 \times 1 0 ^{3}}{T} \Rightarrow T = 400 K$
Hence (B) is correct option.

Q. The enthalpy of vaporization of liquid is 30kJmol−1 and entropy of vapourisation is 75Jmol−1K−1 . The boiling point of the liquid at 1 atm is