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Q. The enthalpy of vaporization of liquid is $30 \, kJ \, mol^{- 1}$ and entropy of vapourisation is $75 \, J \, mol^{- 1}K^{- 1}$ . The boiling point of the liquid at 1 atm is

NTA AbhyasNTA Abhyas 2022

Solution:

$ds=\frac{d q_{r e v}}{T}\Rightarrow 75=\frac{30 \times 10^{3}}{T}\Rightarrow T=400 \, K$
Hence (B) is correct option.