Question

The enthalpy of solution of sodium chloride is $4kJmo{l}^{-1}$ and its enthalpy of hydration of ions is $-784kJmo{l}^{-1}$. Then the lattice enthalpy of $NaCl$ (in $kJmo{l}^{-1}$) is

• A. $+788$
• B. $+4$
• C. $+398$
• D. $+780$
• E. $+394$

Answer 1

Answer: (A)

Correct answer is (a) $+788$