The enthalpy of neutralisation of NH4OH textandCH3COOH is -10.5kcalmol- 1 and enthalpy of neutralisation of CH3COOH with strong base is -12.5kcalmol- 1 .The enthalpy of ionisation of NH4OH will be

Question

The enthalpy of neutralisation of NH4OH textandCH3COOH is -10.5kcalmol- 1 and enthalpy of neutralisation of CH3COOH with strong base is -12.5kcalmol- 1 .The enthalpy of ionisation of NH4OH will be (A) 4.0kcalmol- 1 (B) 3.0kcalmol- 1 (C) 2.0kcalmol- 1 (D) 3.2kcalmol- 1

Tardigrade Admin · Accepted Answer

Δ textH textneutr. textfor strong acid with strong base = - 1 3 ⋅ 7 textkcal equiv-1 Enthalpy of ionisation of acetic acid & NH4OH together = - text10 text.5 - (. - text13 text.7 .) = + text3 ( text.2 kcal mol) text-1 Enthalpy of ionisation of only acetic acid = - text12 text.5 - (. - text13 text.7 .) = + text1 ( text.2 kcal mol) text-1 Enthalpy of ionisation of only NH4OH = text3 text.2 - text1 text.2 = text2 kcal mol text-1

Q. The enthalpy of neutralisation of $N H_{4} O H and C H_{3} COO H$ is $- 10.5 k c a l m o l^{- 1}$ and enthalpy of neutralisation of $C H_{3} COO H$ with strong base is $- 12.5 k c a l m o l^{- 1}$ .The enthalpy of ionisation of $N H_{4} O H$ will be

$4.0 k c a l m o l^{- 1}$

$3.0 k c a l m o l^{- 1}$

$2.0 k c a l m o l^{- 1}$

$3.2 k c a l m o l^{- 1}$

Q. The enthalpy of neutralisation of NH4​OHandCH3​COOH is −10.5kcalmol−1 and enthalpy of neutralisation of CH3​COOH with strong base is −12.5kcalmol−1 .The enthalpy of ionisation of NH4​OH will be

4.0kcalmol−1

3.0kcalmol−1

2.0kcalmol−1

3.2kcalmol−1

Q. The enthalpy of neutralisation of $N H_{4} O H and C H_{3} COO H$ is $- 10.5 k c a l m o l^{- 1}$ and enthalpy of neutralisation of $C H_{3} COO H$ with strong base is $- 12.5 k c a l m o l^{- 1}$ .The enthalpy of ionisation of $N H_{4} O H$ will be

$4.0 k c a l m o l^{- 1}$

$3.0 k c a l m o l^{- 1}$

$2.0 k c a l m o l^{- 1}$

$3.2 k c a l m o l^{- 1}$