The enthalpy of formation of CO(g), CO2(g), N2O(g) and N2O4(g) is -110, -393, +811 and 10 kj/mol respectively. For the reaction, N2O4(g)+3CO(g)→ N2O(g)+3CO2(g).Δ Hr (kJ/mol) is

Question

The enthalpy of formation of CO(g), CO2(g), N2O(g) and N2O4(g) is -110, -393, +811 and 10 kj/mol respectively. For the reaction, N2O4(g)+3CO(g)→ N2O(g)+3CO2(g).Δ Hr (kJ/mol) is (A) - 212 (B) + 212 (C) + 48 (D) - 48

Tardigrade Admin · Accepted Answer

N 2 O 4( g )+3 CO ( g ) longrightarrow N 2 O ( g )+3 CO 2( g ) Δ H text reaction =∑ text Heat of formation of products -∑ text Heat of formation of reactants Δ H text reaction =[Δ Hf N2 O+3 × Δ Hf C O2]-[Δ Hf N2 O4+3 × Δ Hf C O] Δ Hr=[+811+3(-393)]-[10+3(-110)] =[811-1179]-[-320]=-368+320 =-48 kJ / mol

Q. The enthalpy of formation of CO(g),​CO2(g)​,N2​O(g)​ and N2​O4(g)​ is -110, -393, +811 and 10 kj/mol respectively. For the reaction, N2​O4(g)​+3CO(g)​→N2​O(g)​+3CO2(g)​.ΔHr​(kJ/mol) is

- 212

+ 212

+ 48

- 48

Q. The enthalpy of formation of $C O_{(g),} C O_{2 (g)}, N_{2} O_{(g)}$ and $N_{2} O_{4 (g)}$ is -110, -393, +811 and 10 kj/mol respectively. For the reaction,
$N_{2} O_{4 (g)} + 3 C O_{(g)} \to N_{2} O_{(g)} + 3 C O_{2 (g)} .Δ H_{r} (k J / m o l)$ is