The enthalpy of combustion of propane, graphite and dihydrogen at 298 K are: 2220.0 kJ mol -1,-393.5 kJ mol -1 and -285.8 kJ mol -1 respectively. The magnitude enthalpy of formation of propane ( C 3 H 8) is........kJ mol -1. (Nearest integer)

Question

The enthalpy of combustion of propane, graphite and dihydrogen at 298 K are: 2220.0 kJ mol -1,-393.5 kJ mol -1 and -285.8 kJ mol -1 respectively. The magnitude enthalpy of formation of propane ( C 3 H 8) is........kJ mol -1. (Nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

3 C ( gr )+4 H 2( g ) arrow C 3 H 8( g ) =-103.7 kJ mol -1

Q. The enthalpy of combustion of propane, graphite and dihydrogen at $298 K$ are: $2220.0 k J m o l^{- 1}, - 393.5 k J m o l^{- 1}$ and $- 285.8$ $k J m o l^{- 1}$ respectively. The magnitude enthalpy of formation of propane $(C_{3} H_{8})$ is........ $k J m o l^{- 1}$ . (Nearest integer)

$3 C_{(g r)} + 4 H_{2 (g)} \to C_{3} H_{8 (g)}$
$= - 103.7 k J m o l^{- 1}$

Q. The enthalpy of combustion of propane, graphite and dihydrogen at 298K are: 2220.0kJmol−1,−393.5kJmol−1 and −285.8 kJmol−1 respectively. The magnitude enthalpy of formation of propane (C3​H8​) is........kJmol−1. (Nearest integer)

3C(gr)​+4H2(g)​→C3​H8(g)​ =−103.7kJmol−1

Q. The enthalpy of combustion of propane, graphite and dihydrogen at $298 K$ are: $2220.0 k J m o l^{- 1}, - 393.5 k J m o l^{- 1}$ and $- 285.8$ $k J m o l^{- 1}$ respectively. The magnitude enthalpy of formation of propane $(C_{3} H_{8})$ is........ $k J m o l^{- 1}$ . (Nearest integer)

$3 C_{(g r)} + 4 H_{2 (g)} \to C_{3} H_{8 (g)}$
$= - 103.7 k J m o l^{- 1}$