The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1 respectively. The enthalpy of formation of carbon monoxide per mole is

Question

The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1 respectively. The enthalpy of formation of carbon monoxide per mole is (A) -676.9 kJ (B) 676.5 kJ (C) 110.5 kJ (D) -110.5 kJ

Tardigrade Admin · Accepted Answer

C (s)+ O 2(g) longrightarrow CO 2(g) Δ H=-393.5 kJmol -1 CO (g)+(1/2) O 2(g) arrow CO 2(g) Δ H=-283 kJmol -1 On subtracting equation (ii) from equation (i), we get C (s)+ O 2(g) arrow CO (g) ; Δ H=-110.5 kJmol -1 The enthalpy of formation of carbon monoxide per mole =-110.5 kJmol -1

Q. The enthalpies of combustion of carbon and carbon monoxide are −393.5 and −283kJmol−1 respectively. The enthalpy of formation of carbon monoxide per mole is

-676.9 kJ

676.5 kJ

110.5 kJ

-110.5 kJ

C(s)+O2​(g)⟶CO2​(g) ΔH=−393.5kJmol−1 CO(g)+21​O2​(g)→CO2​(g) ΔH=−283kJmol−1 On subtracting equation (ii) from equation (i), we get C(s)+O2​(g)→CO(g);ΔH=−110.5kJmol−1 The enthalpy of formation of carbon monoxide per mole =−110.5kJmol−1

Q. The enthalpies of combustion of carbon and carbon monoxide are $- 393.5$ and $- 283 k J m o l^{- 1}$ respectively. The enthalpy of formation of carbon monoxide per mole is