Question

The energy that will be ideally radiated by a $100kW$ transmitter in $1$ hour is :

• A. $1\times 10^{5}J$
• B. $36\times 10^{7}J$
• C. $36\times 10^{4}J$
• D. $36\times 10^{5}J$

Answer 1

Answer: (B)

$E=P\times t=100\times 10^3\times 3600$
$=36\times 10^{7}J$