The energy stored in the magnetic field if current of 5 A produces a magnetic flux of 2 × 10-3 Wb through a coil of 500 turns is

Question

The energy stored in the magnetic field if current of 5 A produces a magnetic flux of 2 × 10-3 Wb through a coil of 500 turns is (A) 2.5 J (B) 0.25 J (C) 250 J (D) 1.5 J

Tardigrade Admin · Accepted Answer

N φ =L I L=(N φ/I) =(500 × 2 × 10-3/5)=0.2 H. Energy stored, Um=(1/2) L I2=(1/2) × 0.2 ×(5)2=2.5 J

Q. The energy stored in the magnetic field if current of $5 A$ produces a magnetic flux of $2 \times 1 0^{- 3} Wb$ through a coil of 500 turns is

2.5 J

0.25 J

250 J

1.5 J

$Nϕ = L I$
$L = \frac{Nϕ}{I} = \frac{500 \times 2 \times 1 0 ^{- 3}}{5} = 0.2 H .$ Energy stored,
$U_{m} = \frac{1}{2} L I^{2} = \frac{1}{2} \times 0.2 \times (5)^{2} = 2.5 J$

Q. The energy stored in the magnetic field if current of 5A produces a magnetic flux of 2×10−3Wb through a coil of 500 turns is