Question

The energy stored in a $50mH$ inductor carrying a current of $4A$ will be

• A. 0.4 J
• B. 4.0 J
• C. 0.8 J
• D. 0.04 J

Answer 1

Answer: (A)

$U=\frac{1}{2}L{i}^2=\frac{1}{2}\times \left(50\times 10^{-3}\right)\times (4{)}^2$
$=400\times 10^{-3}=0.4J$