The energy required to remove the electron from a singly ionized Helium atom is 2.2 times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is :

Question

The energy required to remove the electron from a singly ionized Helium atom is 2.2 times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is : (A) 20 eV (B) 34 eV (C) 79 eV (D) 109 eV

Tardigrade Admin · Accepted Answer

Energy required to remove electron from a singly ionised Helium atom is given as

E = \frac{13.6 Z ^{2}}{n ^{2}} = \frac{13.6 ( 2 ) ^{2}}{( 1 ) ^{2}}

= 13.6 \times 4 = 54.4 e V

Let energy required to remove an electron from Helium atom is

E^{'}

.
It is given

E = 2.2 E^{'}

. Therefore,

E^{'} = \frac{E}{2.2} = \frac{54.4 e V}{2.2} = 24.7 e V

Thus, total energy required to ionise the Helium atom completely is

E + E^{'} = 54.4 e V + 24.7 e V = 79.1 e V \sim 79 e V

Q. The energy required to remove the electron from a singly ionized Helium atom is 2.2 times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is :

$20 e V$

$34 e V$

$79 e V$

$109 e V$

Q. The energy required to remove the electron from a singly ionized Helium atom is 2.2 times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is :

20eV

34eV

79eV

109eV

$20 e V$

$34 e V$

$79 e V$

$109 e V$