Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The energy required to remove the electron from a singly ionized Helium atom is 2.2 times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is :

JEE MainJEE Main 2018Atoms

Solution:

Energy required to remove electron from a singly ionised Helium atom is given as
$E=\frac{13.6 Z^{2}}{n^{2}}=\frac{13.6(2)^{2}}{(1)^{2}}$
$=13.6 \times 4=54.4\, eV$
Let energy required to remove an electron from Helium atom is $E'$.
It is given $E=2.2 E'$. Therefore,
$E'=\frac{E}{2.2}=\frac{54.4 eV }{2.2}=24.7\, eV$
Thus, total energy required to ionise the Helium atom completely is
$E+E'=54.4\, eV +24.7\, eV =79.1\, eV \sim 79\, eV$