The energy released in the fission of 1 kg of 92U235 is (energy per fission = 200 MeV)

Question

The energy released in the fission of 1 kg of 92U235 is (energy per fission = 200 MeV) (A)  5.1× 1026eV  (B)  5.1× 1026J  (C)  8.2× 1013J  (D)  8.2× 1013MeV

Tardigrade Admin · Accepted Answer

Energy released from 1 kg of uranium =(200× 106× 1.6× 10-19× 6.023× 1026/235) =8.2× 1013J

Q. The energy released in the fission of $1 k g$ of $_{92} U^{235}$ is (energy per fission = 200 MeV)

$5.1 \times 10^{26} e V$

$5.1 \times 10^{26} J$

$8.2 \times 10^{13} J$

$8.2 \times 10^{13} M e V$

$5.1 \times 10^{23} M e V$

Energy released from 1 kg of uranium
$= \frac{200 \times 10 ^{6} \times 1.6 \times 10 ^{- 19} \times 6.023 \times 10 ^{26}}{235}$
$= 8.2 \times 10^{13} J$

Q. The energy released in the fission of 1kg of 92​U235 is (energy per fission = 200 MeV)

5.1×1026eV

5.1×1026J

8.2×1013J

8.2×1013MeV

5.1×1023MeV

Energy released from 1 kg of uranium =235200×106×1.6×10−19×6.023×1026​ =8.2×1013J