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Physics
The energy released in the fission of 1 kg of 92U235 is (energy per fission = 200 MeV)
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Q. The energy released in the fission of $ 1 \,kg $ of $ _{92}{{U}^{235}} $ is (energy per fission = 200 MeV)
KEAM
KEAM 2008
Nuclei
A
$ 5.1\times {{10}^{26}}eV $
B
$ 5.1\times {{10}^{26}}J $
C
$ 8.2\times {{10}^{13}}J $
D
$ 8.2\times {{10}^{13}}MeV $
E
$ 5.1\times {{10}^{23}}MeV $
Solution:
Energy released from 1 kg of uranium
$ =\frac{200\times {{10}^{6}}\times 1.6\times {{10}^{-19}}\times 6.023\times {{10}^{26}}}{235} $
$ =8.2\times {{10}^{13}}J $