The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to produce 3.2 W of power is (Take, 1 e V = 1.6 × 10-19 J)

Question

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to produce 3.2 W of power is (Take, 1 e V = 1.6 × 10-19 J) (A) 107 (B) 1010 (C) 1015 (D) 1011

Tardigrade Admin · Accepted Answer

We have the energy released by fission of one uranium atom is

200 M e V

.
So,

E = 200 \times 1 0^{6} \times 1.6 \times 1 0^{- 19}

= 3.2 \times 1 0^{- 11} J

The power required

= 3.2 W

Thus the number of fissions required is equal to

\frac{3.2}{3.2 \times 1 0 ^{- 11}} = 1 0^{11}

fissions.

Q. The energy released by the fission of one uranium atom is $200 M e V$ . The number of fission per second required to produce $3.2 W$ of power is (Take, $1 e V = 1.6 \times$ $1 0^{- 19} J)$

$1 0^{7}$

$1 0^{10}$

$1 0^{15}$

$1 0^{11}$

We have the energy released by fission of one uranium atom is $200 M e V$ .
So, $E = 200 \times 1 0^{6} \times 1.6 \times 1 0^{- 19}$
$= 3.2 \times 1 0^{- 11} J$
The power required $= 3.2 W$
Thus the number of fissions required is equal to
$\frac{3.2}{3.2 \times 1 0 ^{- 11}} = 1 0^{11}$ fissions.

Q. The energy released by the fission of one uranium atom is 200MeV. The number of fission per second required to produce 3.2W of power is (Take, 1eV=1.6× 10−19J)

107

1010

1015

1011