The energy of an electron in the excited state of H-atom is - 1.5 eV, then according to Bohrs model, its momentum will be:

Question

The energy of an electron in the excited state of H-atom is - 1.5 eV, then according to Bohrs model, its momentum will be: (A)  3.15× 10-34 J- sec  (B)  1.82× 10-34 J- sec  (C)  5.01× 10-30 J- sec  (D)  7.14× 10-31 J- sec

Tardigrade Admin · Accepted Answer

(n2=(13.6/1.5) ⇒ n2=9) ∴ n=3 For 1.5 eV , n=3 Angular momentum =n (h/2 π) =(3 × 6.6 × 10-34/2 × 3.14) =3.15 × 10-34 J - sec

Q. The energy of an electron in the excited state of $H$ -atom is $- 1.5 e V$ , then according to Bohrs model, its momentum will be:

$3.15 \times 1 0^{- 34} J - sec$

$1.82 \times 1 0^{- 34} J - sec$

$5.01 \times 1 0^{- 30} J - sec$

$7.14 \times 1 0^{- 31} J - sec$

$(n^{2} = \frac{13.6}{1.5} \Rightarrow n^{2} = 9)$
$∴ n = 3$
For $1.5 e V, n = 3$
Angular momentum
$= n \frac{h}{2 π}$
$= \frac{3 \times 6.6 \times 1 0 ^{- 34}}{2 \times 3.14}$
$= 3.15 \times 1 0^{- 34} J - sec$

Q. The energy of an electron in the excited state of H-atom is −1.5eV, then according to Bohrs model, its momentum will be:

3.15×10−34J−sec

1.82×10−34J−sec

5.01×10−30J−sec

7.14×10−31J−sec