Question

The energy of a photon is given as $3.03\times 10^{-19}J$. The wavelength of the photon is

• A. $6.56nm$
• B. $65.6nm$
• C. $0.656nm$
• D. $656nm$

Answer 1

Answer: (D)

$E=\frac{hc}{\lambda }$ or $\lambda =\frac{hc}{E}$
$\lambda =\frac{6.626\times 10^{-34}Js\times 3\times 10^{8}m{s}^{-1}}{3.03\times 10^{-19}J}$
$=6.56\times 10^{-7}m$ or $656nm$