Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The energy of a photon is given as $3.03 \times 10^{-19}\,J$. The wavelength of the photon is

Structure of Atom

Solution:

$E=\frac{hc}{\lambda}$ or $\lambda=\frac{hc}{E}$
$\lambda=\frac{6.626 \times 10^{-34}\,J\,s \times 3 \times 10^{8}\,m\,s^{-1}}{3.03 \times 10^{-19}\,J}$
$=6.56\times10^{-7}\,m$ or $656\,nm$