The energy of a photon is 3 × 10-12 erg. What is its wavelength in nm ? (h=6.62 × 10-27 erg -s ; c=3 × 1010 cm / s )

Question

The energy of a photon is 3 × 10-12 erg. What is its wavelength in nm ? (h=6.62 × 10-27 erg -s ; c=3 × 1010 cm / s ) (A) 662 (B) 1324 (C) 66.2 (D) 6.62

Tardigrade Admin · Accepted Answer

E=3 × 10-12 erg λ=? h=6.62 × 10-27 erg - s c=3 × 1010 cm s -1 E=(h c/λ) 3 × 10-2=(6.62 × 10-27 × 3 × 1010/ 10) λ=(6.62 × 10-27 × 3 × 1010/3 × 10-12) =6.62 × 10-5 cm =662 × 10-7 cm =662 × 10-9 m =662 nm

Q. The energy of a photon is 3×10−12 erg. What is its wavelength in nm ? (h=6.62×10−27erg−s;c=3×1010cm/s)

662

1324

66.2

6.62

E=3×10−12erg λ=? h=6.62×10−27erg−s c=3×1010cms−1 E=λhc​ 3×10−2=106.62×10−27×3×1010​ λ=3×10−126.62×10−27×3×1010​ =6.62×10−5cm =662×10−7cm =662×10−9m=662nm

Q. The energy of a photon is $3 \times 1 0^{- 12}$ erg. What is its wavelength in $nm$ ? $(h = 6.62 \times 1 0^{- 27} er g - s; c = 3 \times 1 0^{10} c m / s)$