The energy (in eV) required to excite an electron from n = 2 to n = 4 state in hydrogen atom is

Question

The energy (in eV) required to excite an electron from n = 2 to n = 4 state in hydrogen atom is (A) + 2.55 (B) - 3.4 (C) - 0.85 (D) + 4.25

Tardigrade Admin · Accepted Answer

We know that, En=(13.6/n2) According to question, the required energy is E =E2-E4 =(13.6/(2)2)-(13.6/42)=(13.6/4)-(13.6/16) =((13.6 × 4)-13.6/16) =(40.8/16)=+2.55

Q. The energy (in eV) required to excite an electron from $n = 2$ to $n = 4$ state in hydrogen atom is

+ 2.55

- 3.4

- 0.85

+ 4.25

We know that,
$E_{n} = \frac{13.6}{n ^{2}}$
According to question, the required energy is
$E = E_{2} - E_{4}$
$= \frac{13.6}{( 2 ) ^{2}} - \frac{13.6}{4 ^{2}} = \frac{13.6}{4} - \frac{13.6}{16}$
$= \frac{( 13.6 \times 4 ) - 13.6}{16}$
$= \frac{40.8}{16} = + 2.55$

Q. The energy (in eV) required to excite an electron from n=2 to n=4 state in hydrogen atom is