The energy absorbed by each molecule (A2) of a substance is 4.4 × 10-19 J and bond energy per molecule is 4.0 × 10-19 J. The kinetic energy of the molecule per atom will be

Question

The energy absorbed by each molecule (A2) of a substance is 4.4 × 10-19 J and bond energy per molecule is 4.0 × 10-19 J. The kinetic energy of the molecule per atom will be (A) 2.2 × 10-19 J (B) 2.0 × 10-19 J (C) 4.0 × 10-20 J (D) 2.0 × 10-20 J

Tardigrade Admin · Accepted Answer

Energy absorbed by each molecule =4.4 × 10-19 J Energy required to break the bond =4.0 × 10-19 J Remaining energy gets converted to kinetic energ =(4.4 × 10-19-4.0 × 10-19) J =0.4 × 10-19 J per molecule ∴ Kinetic energy per atom =0.2 × 10-19 J =2 × 10-20 J

Q. The energy absorbed by each molecule $(A_{2})$ of a substance is $4.4 \times 1 0^{- 19} J$ and bond energy per molecule is $4.0 \times 1 0^{- 19} J$ . The kinetic energy of the molecule per atom will be

$2.2 \times 1 0^{- 19} J$

$2.0 \times 1 0^{- 19} J$

$4.0 \times 1 0^{- 20} J$

$2.0 \times 1 0^{- 20} J$

Q. The energy absorbed by each molecule (A2​) of a substance is 4.4×10−19J and bond energy per molecule is 4.0×10−19J. The kinetic energy of the molecule per atom will be

2.2×10−19J

2.0×10−19J

4.0×10−20J

2.0×10−20J

Energy absorbed by each molecule =4.4×10−19J Energy required to break the bond =4.0×10−19J Remaining energy gets converted to kinetic energ =(4.4×10−19−4.0×10−19)J =0.4×10−19J per molecule ∴ Kinetic energy per atom =0.2×10−19J=2×10−20J

Q. The energy absorbed by each molecule $(A_{2})$ of a substance is $4.4 \times 1 0^{- 19} J$ and bond energy per molecule is $4.0 \times 1 0^{- 19} J$ . The kinetic energy of the molecule per atom will be

$2.2 \times 1 0^{- 19} J$

$2.0 \times 1 0^{- 19} J$

$4.0 \times 1 0^{- 20} J$

$2.0 \times 1 0^{- 20} J$