The end product (Y) of the reaction sequence: CH3NHCH3 xrightarrow[NaOH]PhCOCl (X) xrightarrow[H2O]LiAlH4(Y)

Question

The end product (Y) of the reaction sequence: CH3NHCH3 xrightarrow[NaOH]PhCOCl (X) xrightarrow[H2O]LiAlH4(Y) (A) PhN ( CH 3)2 (B) PhCH 2 N ( CH 3)2 (C) PhCH ( OH ) N ( CH 3)2 (D) PhCON ( CH 3)2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/6b9aa84299acba68656013ce7bf62150-.png" /> (- overset underset||OC - NH -) group is N-substituted amide, so by LAH it is converted to (- CH ,- NH ) group.

Q. The end product (Y) of the reaction sequence:
$C H_{3} N H C H_{3} P h COCl N a O H (X) L i A l H_{4} H_{2} O (Y)$

$P h N (C H_{3})_{2}$

$P h C H_{2} N (C H_{3})_{2}$

$P h C H (O H) N (C H_{3})_{2}$

$P h CON (C H_{3})_{2}$

$(- C ∣∣ O - N H -)$ group is $N$ -substituted amide, so by $L A H$ it is converted to $(- C H, - N H)$ group.

Q. The end product (Y) of the reaction sequence: CH3​NHCH3​PhCOClNaOH​(X)LiAlH4​H2​O​(Y)

PhN(CH3​)2​

PhCH2​N(CH3​)2​

PhCH(OH)N(CH3​)2​

PhCON(CH3​)2​