Question

The end product of the ${\beta }^{-}$ decay of ${}_{15}^{32}P$ is

• A. ${}_{16}^{32}\mathrm{S}$
• B. ${}_{16}^{35}\mathrm{S}$
• C. ${}_{14}^{32}\mathrm{N}$
• D. ${}_{17}^{32}\mathrm{Cl}$

Answer 1

Answer: (A)

The following equation shows the ${\beta }^{-}$ decay of ${}_{15}^{32}P$
${}_{15}^{32}P{\to }_{16}^{32}S+{\beta }^{-}$
${}_{15}^{32}\mathrm{P}\to {}_{16}^{32}\mathrm{S}+{}_{-1}^0\mathrm{e}$