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Q. The end product of the $\beta ^{-}$ decay of $_{15}^{32}P$ is

NTA AbhyasNTA Abhyas 2020Nuclei

Solution:

The following equation shows the $\beta ^{-}$ decay of $_{15}^{32}P$
$_{15}^{32}P \rightarrow _{16}^{32}S+\beta ^{-}$
${ }_{15}^{32} \mathrm{P} \rightarrow{ }_{16}^{32} \mathrm{~S}+{ }_{-1}^0 \mathrm{e}$