Question

The end correction of a resonance column is $1cm$. If the shortest length resonating with the tuning fork is $10cm$, the next resonating length should be :

• A. 28 cm
• B. 32 cm
• C. 36 cm
• D. 40 cm

Answer 1

Answer: (B)

Let $x$ be the end correction and $l_2$ be the second resonance length.
Given: first resonance length, $l_1=10cm$ and end correction of a resonance column, $x=1cm$.
For first resonance, we have

$\frac{\lambda }{4}=l_1+x$
$\frac{\lambda }{4}=10+1=11cm$
$\lambda =44cm$
For next resonance, that is, second resonance,

$\frac{3\lambda }{4}=l_2+x$
$3\times 11=l_2+1$ or $33=l_2+1$
$l_2=32cm$