The emf of the following three cells I. Z n| Z n2+(1 M)|| C u2(1 M)| C u II. Z n| Z n2+(0.1 M)|| C u2(1 M)| C u III. Z n| Z n2+(1 M)|| C u2+(0.1 M)| C u are represented by E1, E2 and E3. Which of the following statement is correct?

Question

The emf of the following three cells I. Z n| Z n2+(1 M)|| C u2(1 M)| C u II. Z n| Z n2+(0.1 M)|| C u2(1 M)| C u III. Z n| Z n2+(1 M)|| C u2+(0.1 M)| C u are represented by E1, E2 and E3. Which of the following statement is correct? (A) E1>E2>E3 (B) E3>E2>E1 (C) E3>E1>E2 (D) E2>E1>E3

Tardigrade Admin · Accepted Answer

Z n +C u2+ arrow Z n2++C u From Nernst equation, E text cell =E text cell o-(0.591/n) log ([ text Product ]/[ text Reactant ]) E1=-(0.0591/2) log (1 M/1 M)=0 E2=-(0.0591/2) log (0.1 M/1 M)=+0.02955 E3=-(0.0591/2) log (1 M/0.1 M)=-0.0591 Thus, E2>E1>E3

$E_{1} > E_{2} > E_{3}$

$E_{3} > E_{2} > E_{1}$

$E_{3} > E_{1} > E_{2}$

$E_{2} > E_{1} > E_{3}$

E1​>E2​>E3​

E3​>E2​>E1​

E3​>E1​>E2​

E2​>E1​>E3​

Zn+Cu2+→Zn2++Cu From Nernst equation, Ecell ​=Ecell o​−n0.591​log[ Reactant ][ Product ]​ E1​=−20.0591​log1M1M​=0 E2​=−20.0591​log1M0.1M​=+0.02955 E3​=−20.0591​log0.1M1M​=−0.0591 Thus, E2​>E1​>E3​

$E_{1} > E_{2} > E_{3}$

$E_{3} > E_{2} > E_{1}$

$E_{3} > E_{1} > E_{2}$

$E_{2} > E_{1} > E_{3}$