The emf of the cell involving following changes, Zn(s)+Ni2+(1M) xrightarrow[]Zn2+(1M)+Ni(s) is 0.5105 V. The standard emf of the cell is

Question

The emf of the cell involving following changes, Zn(s)+Ni2+(1M) xrightarrow[]Zn2+(1M)+Ni(s) is 0.5105 V. The standard emf of the cell is (A) 0.540V (B) 0.4810V (C) 0.5696V (D) 0.5105V

Tardigrade Admin · Accepted Answer

Ecell=Ecello+(0.059/2) log ([Ni2+]/[Zn2+]) 0.5105=Ecello+(0.059/2) log (1/1) Ecello=0.5105 (∵ log 1=0)

Q. The emf of the cell involving following changes, $Z n (s) + N i^{2 +} (1 M) Z n^{2 +} (1 M) + N i (s)$ is 0.5105 V. The standard emf of the cell is

0.540V

0.4810V

0.5696V

0.5105V

$E_{ce ll} = E_{ce ll}^{o} + \frac{0.059}{2} lo g \frac{[ N i ^{2 +} ]}{[ Z n ^{2 +} ]}$
$0.5105 = E_{ce ll}^{o} + \frac{0.059}{2} lo g \frac{1}{1}$
$E_{ce ll}^{o} = 0.5105$
$(∵ lo g 1 = 0)$

Q. The emf of the cell involving following changes, Zn(s)+Ni2+(1M)​Zn2+(1M)+Ni(s) is 0.5105 V. The standard emf of the cell is