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  4. The emf of the cell involving following changes, Zn(s)+Ni2+(1M) xrightarrow[]Zn2+(1M)+Ni(s) is 0.5105 V. The standard emf of the cell is

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Q. The emf of the cell involving following changes, $ Zn(s)+N{{i}^{2+}}(1M)\xrightarrow[{}]{{}}Z{{n}^{2+}}(1M)+Ni(s) $ is 0.5105 V. The standard emf of the cell is

Rajasthan PETRajasthan PET 2011

Solution:

$ {{E}_{cell}}=E_{cell}^{o}+\frac{0.059}{2}\log \frac{[N{{i}^{2+}}]}{[Z{{n}^{2+}}]} $
$ 0.5105=E_{cell}^{o}+\frac{0.059}{2}\log \frac{1}{1} $
$ E_{cell}^{o}=0.5105 $
$ (\because \log 1=0) $