The elongation of a wire on the surface of the earth is 10-4 m. The same wire of same dimensions is elongated by 6 × 10-5 m on another planet. The acceleration due to gravity on the planet will be..... ms -2. (Take acceleration due to gravity on the surface of earth =10 m / s -2 )

Question

The elongation of a wire on the surface of the earth is 10-4 m. The same wire of same dimensions is elongated by 6 × 10-5 m on another planet. The acceleration due to gravity on the planet will be..... ms -2. (Take acceleration due to gravity on the surface of earth =10 m / s -2 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Δ ℓ propto g (Δ ℓ text earth /Δ ℓ text planet )=( g text earth / g text planet )=(10-4/6 × 10-5) g text planet =6 m / s 2

Q. The elongation of a wire on the surface of the earth is 10−4m. The same wire of same dimensions is elongated by 6×10−5m on another planet. The acceleration due to gravity on the planet will be..... ms−2. (Take acceleration due to gravity on the surface of earth =10m/s−2 )

Δℓ∝g Δℓplanet ​Δℓearth ​​=gplanet ​gearth ​​=6×10−510−4​ gplanet ​=6m/s2

$Δ ℓ \propto g$
$\frac{Δ ℓ _{earth}}{Δ ℓ _{planet}} = \frac{g _{earth}}{g _{planet}} = \frac{1 0 ^{- 4}}{6 \times 1 0 ^{- 5}}$
$g_{planet} = 6 m / s^{2}$