The elevator shown in figure is descending, with an acceleration of 2 m s -2 . The mass of the block A is 0.5 kg and the mass of the block B is 1 kg . The force exerted by the block A on the block B is (Take .g=10 m s -2)

Question

The elevator shown in figure is descending, with an acceleration of 2 m s -2 . The mass of the block A is 0.5 kg and the mass of the block B is 1 kg . The force exerted by the block A on the block B is (Take .g=10 m s -2) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/e841a112b0ed01066a148b0440cf8ee7-.png" /> (A) 2 N (B) 4 N (C) 6 N (D) 8 N

Tardigrade Admin · Accepted Answer

From free body diagram of block A 0.5 g-N=0.5 × 2 or N=0.5 g-0.5 × 2 =0.5(10-2)=4 N <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/fb23b4f7a07d74467f9b02cf6e6588ce-.png" />

Q. The elevator shown in figure is descending, with an acceleration of $2 m s^{- 2} .$ The mass of the block $A$ is $0.5 k g$ and the mass of the block $B$ is $1 k g .$ The force exerted by the block $A$ on the block $B$ is (Take $g = 10 m s^{- 2})$

2 N

4 N

6 N

8 N

From free body diagram of block $A$
$0.5 g - N = 0.5 \times 2$
or $N = 0.5 g - 0.5 \times 2$
$= 0.5 (10 - 2) = 4 N$

Q. The elevator shown in figure is descending, with an acceleration of 2ms−2. The mass of the block A is 0.5kg and the mass of the block B is 1kg. The force exerted by the block A on the block B is (Take g=10ms−2)

2 N

4 N

6 N

8 N

From free body diagram of block A 0.5g−N=0.5×2 or N=0.5g−0.5×2 =0.5(10−2)=4N

Q. The elevator shown in figure is descending, with an acceleration of $2 m s^{- 2} .$ The mass of the block $A$ is $0.5 k g$ and the mass of the block $B$ is $1 k g .$ The force exerted by the block $A$ on the block $B$ is (Take $g = 10 m s^{- 2})$

From free body diagram of block $A$
$0.5 g - N = 0.5 \times 2$
or $N = 0.5 g - 0.5 \times 2$
$= 0.5 (10 - 2) = 4 N$