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Q. The elevator shown in figure is descending, with an acceleration of $2 \,m \,s ^{-2} .$ The mass of the block $A$ is $0.5\, kg$ and the mass of the block $B$ is $1\, kg .$ The force exerted by the block $A$ on the block $B$ is (Take $\left.g=10\, m\, s ^{-2}\right)$
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Laws of Motion

Solution:

From free body diagram of block $A$
$0.5 g-N=0.5 \times 2 $
or $N=0.5 g-0.5 \times 2 $
$=0.5(10-2)=4 N$
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