The elevation in boiling point, when 13.44 g of freshly prepared CuCl 2 are added to one kilogram of water, is [Some useful data, K b=0.52 K kg mol -1, molecular weight of CuCl 2=134.4 g ]

Question

The elevation in boiling point, when 13.44 g of freshly prepared CuCl 2 are added to one kilogram of water, is [Some useful data, K b=0.52 K kg mol -1, molecular weight of CuCl 2=134.4 g ] (A) 0.05 (B) 0.1 (C) 0.16 (D) 0.21

Tardigrade Admin · Accepted Answer

Molality =(13.44/134.1)=0.1 i=3 ⇒ Δ Tb =iKb .m =3 × 0.52 × 0.1 =0.156

Q. The elevation in boiling point, when $13.44 g$ of freshly prepared $C u C l_{2}$ are added to one kilogram of water, is
[Some useful data, $K_{b} = 0.52 K k g m o l^{- 1}$ , molecular weight of $C u C l_{2} = 134.4 g$ ]

0.05

0.1

0.16

0.21

Molality $= \frac{13.44}{134.1} = 0.1$
$i = 3$
$\Rightarrow Δ T_{b} = i K_{b} . m = 3 \times 0.52 \times 0.1 = 0.156$

Q. The elevation in boiling point, when 13.44g of freshly prepared CuCl2​ are added to one kilogram of water, is [Some useful data, Kb​=0.52Kkgmol−1, molecular weight of CuCl2​=134.4g ]

0.05

0.1

0.16

0.21

Molality =134.113.44​=0.1 i=3 ⇒ΔTb​=iKb​.m=3×0.52×0.1=0.156

Q. The elevation in boiling point, when $13.44 g$ of freshly prepared $C u C l_{2}$ are added to one kilogram of water, is
[Some useful data, $K_{b} = 0.52 K k g m o l^{- 1}$ , molecular weight of $C u C l_{2} = 134.4 g$ ]

Molality $= \frac{13.44}{134.1} = 0.1$
$i = 3$
$\Rightarrow Δ T_{b} = i K_{b} . m = 3 \times 0.52 \times 0.1 = 0.156$