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Question
Physics
The electrostatics force of repulsion between two positively charged ions carrying equal charge is 3.7× 10-7N, when they are separated by a distance of 5 overset texto mathop textA . What are the number of electrons are missing each ion?
Q. The electrostatics force of repulsion between two positively charged ions carrying equal charge is
3.7
×
10
−
7
N
,
when they are separated by a distance of 5
A
o
. What are the number of electrons are missing each ion?
2005
174
CMC Medical
CMC Medical 2015
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A
2
B
4
C
5
D
10
Solution:
From Coulambs law
F
=
4
π
ε
0
1
.
r
2
q
1
q
2
3.7
×
10
−
9
=
9
×
10
9
×
(
5
×
10
−
10
)
2
q
2
q
=
3.2
×
10
−
19
c
q
=
n
c
n
=
c
q
=
1.6
×
10
−
10
3.2
×
10
−
19
=
2