Question

The electrostatic potential energy between proton and electron separated by a distance $1\stackrel{\text{o}}{A}$ is

• A. 13.6 eV
• B. 27.2 eV
• C. 14.4 eV
• D. 1.44eV
• E. 28.8 eV

Answer 1

Answer: (C)

$U=\frac{1}{4\pi {\epsilon }_0}\frac{q_1{q}_1}{r}$
$\therefore$ $U=\frac{9\times {10}^9\times (1.6\times {10}^{-19})(-1.6\times {10}^{-19})}{{10}^{-10}}J$
$=-9\times {10}^9\times 1.6\times {10}^{-19}\times {10}^{10}eV$
$=-14.4eV$