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Q. The electrostatic potential energy between proton and electron separated by a distance $ 1\overset{\text{o}}{\mathop{\text{A}}}\, $ is

KEAMKEAM 2007Electrostatic Potential and Capacitance

Solution:

$ U=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{1}}}{r} $
$ \therefore $ $ U=\frac{9\times {{10}^{9}}\times (1.6\times {{10}^{-19}})(-1.6\times {{10}^{-19}})}{{{10}^{-10}}}J $
$ =-9\times {{10}^{9}}\times 1.6\times {{10}^{-19}}\times {{10}^{10}}eV $
$ =-14.4eV $