The electronic configuration of P in H3PO4 is

Question

The electronic configuration of P in H3PO4 is (A) 1 s2 2 s2 2 p6 3 s2 3 p6 (B) 1 s2 2 s2 2 p6 3 s2 (C) 1 s2 2 s2 2 p6 (D) 1 s2 2 s2 2 p6 3 s2 3 p6 4 s1

Tardigrade Admin · Accepted Answer

The electronic configuration of P in H 3 PO 4 is 1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 P atom has 5 valence electrons. It shares 3 with 3 - OH groups to form 3 P - OH bonds. It shares 2 with one O atom to form P = O bond.

Q. The electronic configuration of $P$ in $H_{3} P O_{4}$ is

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}$

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}$

$1 s^{2} 2 s^{2} 2 p^{6}$

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}$

The electronic configuration of $P$ in $H_{3} P O_{4}$ is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}$
$P$ atom has 5 valence electrons. It shares 3 with 3 - $O H$ groups to form $3 P -$ $O H$ bonds. It shares 2 with one $O$ atom to form $P = O$ bond.

Q. The electronic configuration of P in H3​PO4​ is

1s22s22p63s23p6

1s22s22p63s2

1s22s22p6

1s22s22p63s23p64s1