Question

The electronic configuration of nitrogen in nitrous acid is

• A. $1s^2,2s^2$
• B. $1s^2,2s^2,2p^3$
• C. $1s^2,2s^2,2p^1$
• D. $1s^2,2s^2,2p_x^{1}2p_y^{1}2p_z^1$

Answer 1

Answer: (A)

$HN{O}_2$ Oxidation state of N in $HN{O}_2$ is $+1+x-4=0$
$\Rightarrow x-3=0,x=+3$
$N(7):1s^2,2s^2,2p^3\Rightarrow N^{3+}:1s^2,2s^2$