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Q. The electronic configuration of nitrogen in nitrous acid is

COMEDKCOMEDK 2006Structure of Atom

Solution:

$HNO_2$ Oxidation state of N in $HNO_2$ is $+ 1 + x - 4 = 0 $
$\Rightarrow \, x - 3 = 0 ,x = + 3 $
$N(7) : 1s^2, 2s^2, 2p^3 \Rightarrow \: N^{3+} : 1s^2, 2s^2$