The electronic configuration of four elements L, P, Q and R are given in brackets L (1s2, 2s2, 2p4); P (1s2, 2s2 2p6 3s1) Q (1s2, 2s22p6, 3s2 3p5); R (1s2,2s2 2p6, 3s2) The formulae of ionic compounds that can be formed between these elements are

Question

The electronic configuration of four elements L, P, Q and R are given in brackets L (1s2, 2s2, 2p4); P (1s2, 2s2 2p6 3s1) Q (1s2, 2s22p6, 3s2 3p5); R (1s2,2s2 2p6, 3s2) The formulae of ionic compounds that can be formed between these elements are (A) L2P, RL, PQ and R2Q (B) LP, RL, PQ and RQ (C) P2L, RL, PQ and RQ2 (D) LP, R2L, P2Q and RQ

Tardigrade Admin · Accepted Answer

Valencies of L, Q, P and R is -2, -1 , +1 and +2 respectively so they will form P2L, RL, PQ and RQ2

$L_{2} P, R L, PQ$ and $R_{2} Q$

$L P, R L, PQ$ and $RQ$

$P_{2} L, R L, PQ$ and $R Q_{2}$

$L P, R_{2} L, P_{2} Q$ and $RQ$

Valencies of $L, Q, P$ and $R$ is $- 2, - 1, + 1$ and $+ 2$ respectively so they will form $P_{2} L, R L, PQ$ and $R Q_{2}$

Q. The electronic configuration of four elements L,P,Q and R are given in brackets L(1s2,2s2,2p4); P(1s2,2s22p63s1) Q(1s2,2s22p6,3s23p5); R(1s2,2s22p6,3s2) The formulae of ionic compounds that can be formed between these elements are

L2​P,RL,PQ and R2​Q

LP,RL,PQ and RQ

P2​L,RL,PQ and RQ2​

LP,R2​L,P2​Q and RQ

Valencies of L,Q,P and R is −2,−1,+1 and +2 respectively so they will form P2​L,RL,PQ and RQ2​

$L_{2} P, R L, PQ$ and $R_{2} Q$

$L P, R L, PQ$ and $RQ$

$P_{2} L, R L, PQ$ and $R Q_{2}$

$L P, R_{2} L, P_{2} Q$ and $RQ$

Valencies of $L, Q, P$ and $R$ is $- 2, - 1, + 1$ and $+ 2$ respectively so they will form $P_{2} L, R L, PQ$ and $R Q_{2}$