The electronic configuration of an element with atomic number 7 i.e. nitrogen atom is

Question

The electronic configuration of an element with atomic number 7 i.e. nitrogen atom is (A) 1s2, 2s1, 2p3x (B) 1s2,2s2 p1x2p2y (C) 1s2,2s2 2p1x 2p1y 2p1z (D) 1s2,2s22p1x2p2y

Tardigrade Admin · Accepted Answer

7N=1s2,2s22p1x 2p1y,2p1z . Hund’s rule states that pairing of electrons in the orbitals of a subshell (orbitals of equal energy) starts when each of them is singly filled.

Q. The electronic configuration of an element with atomic number $7$ i.e. nitrogen atom is

$1 s^{2}, 2 s^{1}, 2 p_{x}^{3}$

$1 s^{2}, 2 s^{2} p_{x}^{1} 2 p_{y}^{2}$

$1 s^{2}, 2 s^{2} 2 p_{x}^{1} 2 p_{y}^{1} 2 p_{z}^{1}$

$1 s^{2}, 2 s^{2} 2 p_{x}^{1} 2 p_{y}^{2}$

$_{7} N = 1 s^{2}, 2 s^{2} 2 p_{x}^{1} 2 p_{y}^{1}, 2 p_{z}^{1}$ . Hund’s rule states that pairing of electrons in the orbitals of a subshell (orbitals of equal energy) starts when each of them is singly filled.

Q. The electronic configuration of an element with atomic number 7 i.e. nitrogen atom is

1s2,2s1,2px3​

1s2,2s2px1​2py2​

1s2,2s22px1​2py1​2pz1​

1s2,2s22px1​2py2​