The electronegativity of H and Cl are 2.1 and 3.0 respectively. The correct statement about the nature of HCl is

Question

The electronegativity of H and Cl are 2.1 and 3.0 respectively. The correct statement about the nature of HCl is (A) 17% ionic (B) 83% ionic (C) 50% ionic (D) 100% ionic

Tardigrade Admin · Accepted Answer

% ionic character = 16(χA - χB) + 3.5(χA - χB)2 (Here χA and χB are the electronegativities of bonded atoms of chlorine and hydrogen) = 16(3.0 - 2.1) + 3.5(3.0 - 2.1)2 = 14.4 + 2.835 = 17.235 ≈ 17%

Q. The electronegativity of H and Cl are 2.1 and 3.0 respectively. The correct statement about the nature of HCl is

17% ionic

83% ionic

50% ionic

100% ionic

% ionic character $= 16 (χ_{A} - χ_{B}) + 3.5 (χ_{A} - χ_{B})^{2}$
(Here $χ_{A}$ and $χ_{B}$ are the electronegativities of bonded atoms of chlorine and hydrogen)
$= 16 (3.0 - 2.1) + 3.5 (3.0 - 2.1)^{2}$
$= 14.4 + 2.835 = 17.235 \approx 17$ %

Q. The electronegativity of H and Cl are 2.1 and 3.0 respectively. The correct statement about the nature of HCl is

17% ionic

83% ionic

50% ionic

100% ionic

% ionic character =16(χA​−χB​)+3.5(χA​−χB​)2 (Here χA​ and χB​ are the electronegativities of bonded atoms of chlorine and hydrogen) =16(3.0−2.1)+3.5(3.0−2.1)2 =14.4+2.835=17.235≈17%

% ionic character $= 16 (χ_{A} - χ_{B}) + 3.5 (χ_{A} - χ_{B})^{2}$
(Here $χ_{A}$ and $χ_{B}$ are the electronegativities of bonded atoms of chlorine and hydrogen)
$= 16 (3.0 - 2.1) + 3.5 (3.0 - 2.1)^{2}$
$= 14.4 + 2.835 = 17.235 \approx 17$ %