The electron affinity of chlorine is 3.7 eV. 1 gram of chlorine is completely converted to Cl- ion in a gaseous state. (1 eV = 23.06 kcal mol-1). Energy released in the process is

Question

The electron affinity of chlorine is 3.7 eV. 1 gram of chlorine is completely converted to Cl- ion in a gaseous state. (1 eV = 23.06 kcal mol-1). Energy released in the process is (A) 4.8 kcal (B) 7.2 kcal (C) 8.2 kcal (D) 2.4 kcal

Tardigrade Admin · Accepted Answer

Number of moles =(1/35.5) Given, 1 eV = 23.06 kcal mol-1 3.7 eV = 3.7 × 23.06 kcal mol-1 i.e. 1 mole realease energy =3.7×23.06 kcal ∴ Energy released =(1/35.5)×3.7×23.06 kcal=2.4 kcal

Q. The electron affinity of chlorine is $3.7 e V . 1$ gram of chlorine is completely converted to $C l^{-}$ ion in a gaseous state. $(1 e V = 23.06 k c a l m o l^{- 1})$ . Energy released in the process is

$4.8 k c a l$

$7.2 k c a l$

$8.2 k c a l$

$2.4 k c a l$

Number of moles $= \frac{1}{35.5}$
Given, $1 e V = 23.06 k c a l m o l^{- 1}$
$3.7 e V = 3.7 \times 23.06 k c a l m o l^{- 1}$
i.e. 1 mole realease energy
$= 3.7 \times 23.06 k c a l$
$∴$ Energy released
$= \frac{1}{35.5} \times 3.7 \times 23.06 k c a l = 2.4 k c a l$

Q. The electron affinity of chlorine is 3.7eV.1 gram of chlorine is completely converted to Cl− ion in a gaseous state. (1eV=23.06kcalmol−1). Energy released in the process is

4.8kcal

7.2kcal

8.2kcal

2.4kcal