The electromotive force of primary cell is 2 V . When it is short circuited it gives a current of 4 A . Its internal resistance in ohm is

Question

The electromotive force of primary cell is 2 V . When it is short circuited it gives a current of 4 A . Its internal resistance in ohm is (A) 0.5 (B) 5.0 (C) 2.0 (D) 8.0

Tardigrade Admin · Accepted Answer

When cell is short circuited, then total resistance is equal to internal resistance of coil. E=i r r=(E/i)=(2/4)=0.5 ohm

Q. The electromotive force of primary cell is $2 V$ . When it is short circuited it gives a current of $4 A$ . Its internal resistance in ohm is

0.5

5.0

2.0

8.0

When cell is short circuited, then total resistance is equal to internal resistance of coil.
$E = i r$
$r = \frac{E}{i} = \frac{2}{4} = 0.5 o hm$

Q. The electromotive force of primary cell is 2V . When it is short circuited it gives a current of 4A . Its internal resistance in ohm is

0.5

5.0

2.0

8.0

When cell is short circuited, then total resistance is equal to internal resistance of coil. E=ir r=iE​=42​=0.5ohm

Q. The electromotive force of primary cell is $2 V$ . When it is short circuited it gives a current of $4 A$ . Its internal resistance in ohm is

When cell is short circuited, then total resistance is equal to internal resistance of coil.
$E = i r$
$r = \frac{E}{i} = \frac{2}{4} = 0.5 o hm$