The electrochemical extraction of aluminum from bauxite ore involves.

Question

The electrochemical extraction of aluminum from bauxite ore involves. (A) the reaction of Al 2 O 3 with coke (C) at a temperature >2500° C. (B) the neutralization of aluminate solution by passing CO 2 gas to precipitate hydrated alumina ( Al 2 O 3 .3 H 2 O ) (C) the dissolution of Al 2 O 3 in hot aqueous NaOH. (D) the electrolysis of Al 2 O 3 mixed with Na 3 AlF 6 to give Al and CO 2.

Tardigrade Admin · Accepted Answer

(A) Electrochemical extraction of Aluminum from bauxite done below

250 0^{\circ} C

(B)

2 N a [A l (O H)_{4}]_{a q .} + 2 C O_{2 (g)} \to A l_{2} O_{3} .3 H_{2} O_{(s)} ↓ + 2 N a H C O_{3 (a q .)}

The sodium aluminate present in solution is neutralised by passing

C O_{2}

gas and hydrated

A l_{2} O_{3}

is precipitated.
(C)

A l_{2} O_{3 (s)} + 2 N a O H_{(aq.)} + 3 H_{2} O_{(l)} \to 2 N a [A l (O H)_{4}]_{aq.}

Concentration of bauxite is carried out by heating the powdered ore with hot concentrated solution of

N a O H

(D) In metallurgy of aluminum,

A l_{2} O_{3}

is mixed with

N a_{3} A l F_{6}

Q. The electrochemical extraction of aluminum from bauxite ore involves.

the reaction of $A l_{2} O_{3}$ with coke (C) at a temperature $> 250 0^{\circ} C$ .

the neutralization of aluminate solution by passing $C O_{2}$ gas to precipitate hydrated alumina $(A l_{2} O_{3} .3 H_{2} O)$

the dissolution of $A l_{2} O_{3}$ in hot aqueous $N a O H$ .

the electrolysis of $A l_{2} O_{3}$ mixed with $N a_{3} A l F_{6}$ to give $A l$ and $C O_{2}$ .

Q. The electrochemical extraction of aluminum from bauxite ore involves.

the reaction of Al2​O3​ with coke (C) at a temperature >2500∘C.

the neutralization of aluminate solution by passing CO2​ gas to precipitate hydrated alumina (Al2​O3​.3H2​O)

the dissolution of Al2​O3​ in hot aqueous NaOH.

the electrolysis of Al2​O3​ mixed with Na3​AlF6​ to give Al and CO2​.

the reaction of $A l_{2} O_{3}$ with coke (C) at a temperature $> 250 0^{\circ} C$ .

the neutralization of aluminate solution by passing $C O_{2}$ gas to precipitate hydrated alumina $(A l_{2} O_{3} .3 H_{2} O)$

the dissolution of $A l_{2} O_{3}$ in hot aqueous $N a O H$ .

the electrolysis of $A l_{2} O_{3}$ mixed with $N a_{3} A l F_{6}$ to give $A l$ and $C O_{2}$ .